Question

An angle measures 76° more than the measure of its complementary angle. What is the measure of each angle?​

Answer 1

$\huge \mathfrak \red{answer}$

Given:

An angle measure 76° more than the measure it's complementary angle. what is the measure of each angle

$\sf{supplemantary \: angles = 180}$

so

$\sf{let \: one \: angle \: be \: x}$

$\sf{other \: angle \: is \: x + 70}$

so now given

$\rm{x + x + 70 = 180}$

$\rm{2x + 70 = 180}$

now we have to subtract from two sides

$\rm{2x = 180 - 70 = 110}$

then divide the both sides by 2

$\rm \red{x = \frac{110}{2} = 55}$

$\tt \red{now \: angles \: are \: 55 \: nd \: 55 + 70 = 125}$

Answer 2

Answer:

7°  and 83°

Step-by-step explanation:

✯✯Given✯✯

An angle measures 76° more than the measure of its complementary angle.

Let the smaller angle be 'x'.

Then according to the question,

Bigger angle= x+76°

☛Note:

• Complementary angles are those angles whose sum is equal to 90°.

Therefore,

  x+x+76°= 90°

[Since, both angles are complementary angles]

⇒ 2x= 90°-76°

⇒ 2x= 14°

$\implies\sf{x=\dfrac{14}{2} ={7}^{\circ}}$

$\bf{Hence,}$ $\bf {\purple{Smaller\:angle=x={7}^{\circ}}}$

            $\bf {\green{Bigger\:angle=x+{76}^{\circ}={7}^{\circ}+{76}^{\circ}={83}^{\circ}}}$