an angle of a parallelogram is 'x' the adjecent angle to the first one is '2/3x' find the angles of parallelogram ABCD
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2
One angle of llgm = x
Adjacent angle of llgm = 2/3x
Now,
x + 2/3x = 180° [ Co. Interior angles]
=> 5/3x = 180
=> x = 180 * 3/5
=> x = 108
Thus angles of llgm
= 108°, 72°,108°and 72°
Hope it helps...!!!
Answered by
3
x=108
so,
2 * 108 (* means multiply)
3
= 72
$$72,108,72,108 are the angles$$
hope its help u
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