Question

An angle of a triangle is 15° more than third angle is 25° more than twice the second angle . find three angles of the triangle?​

Answer 1

Let x be th first angle.

Then, 2x+25 = 2nd angle

x+15=3rd angle

x+2x+25+x+15=180° [ angle sum property of triangle]

4x+40=180°

4x=140°

x=35°

2x+25=95°

x+15=50°

Therefore...

1st angle=35º

2nd angle=95º

3rd angle=50º

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Answer 2

Answer:

The three angles are 35°,50°,95°

Step-by-step explanation:

let the unknown angles be x

1 angle=15°more than third angle

=15°+x

2 angle=x

3 angle=25°more than the twice of second angle

=25°+2x

so,

(15°+x)+x+(25°+2x)=180(sum of all angles)

4x+40° = 180°

4x = 180°-40°

= 140°

x = 140°÷4

= 35°

first angle = 15°+x

= 15°+35°

=50°

second angle=35°

third angle = 25°+2x

= 25°+2(35)

= 25°+70

95°

check = 35°+50°+95°=180°