Question

An ant climbing up a vertical pole ascends 12 metres and slips down 5 metres in every
alternate hour. If the pole is 63 metres high, how long will it take it to reach the top?​

Answer 1

Solution :

It is given that an ant climbing up a vertical pole ascends 12 meters and slips down 5 meters in every alternate hour .

For example, it travels 12 metres in the 1st hour and slips 5 meters in the next hour.

So, it traveled a net distance of 7 metres in 2 hours.

The pole is 63m high.

In the first 16 hours;

Distance traveled by the ant :

》 56 m

On the 17th hour , it covers the remaining distance and reaches the top .

It won't fall back after it reaches the top .

So , the total time taken by it to reach the top is 17 hours.

This is the required answer .

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Answer 2

Given:-

• An ant climbing up a vertical pole ascends 12 metres and slips down 5 metres in every alternate hour. If the pole is 63 metres high, how long will it take it to reach the top?

To Find:-

• how long will it take it to reach the top?

Solution:-

As the Ant climbs the pole 12 meters in an hour it recedes back 5 meters in the next hour.

So the rate of ascending up by the Ant will be:

~ 12–5= 7metres per 2hours

Then in next 2 hours Ant will be at 14m above.. So on

~14m in 4 hours

~21m in 6 hours

~28m in 8 hours o

~35m in 10 hours

~ 42m in 12 hours

~49m in 14 hours

~56m in 16 hours…now remaining height is 7metres

But rate of ascending in one hour is 12 m

So we only have to occupy the remaining 7 m height

So( 7÷12) ×60 in minutes= 35 mins

So the time taken by the Ant to climb the Pole top is 16 hours and 35 minutes.

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