Question

An ant climbs up 12m in a hour and then slips down 5m in the alternate hour.Find the total time taken by the ant.​

Answer 1

Answer:

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An ant climbs up 12 m in a hour and the slips down 5 m in the alternate hour.Find the total time taken by the ant.

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This means the ant is actually climbing only (12-5)m=7m in 2 hour.

So,in 2 hours,the ant climbs 7 m.

4 hours⇒14 m;16 hours⇒7×8=50 m.

Now,the distance left for the ant to climb is (63-56)m=7m.

We know that the ant climbs 12 m in an hour and then slips 5m in the next hour.(given)

So,the ant can climb 7m without slipping.Time it will be take=7/12 hour.

$\sf{12m = 1m}\\ \sf{1m = \frac{1}{12} \: hour } \\ \sf{7m = \frac{1}{12} \times 7 = \frac{7}{12} \: hour }$

Converting 7/12 hour into minutes,(7/12)×60=35 minutes.(1 hr=60 min)

Total time taken=16 hours(For 56 m)+35 minutes(For 7 m)

Total time taken=16 hours 35 minutes.