Question

An Ant climbs up five stairs each of the width 20cm and height 20cm. Find the distance covered and displacement.
Can anyone please answer this question?????

Answer 1

Given that, an ant climbs up five stairs each of the width 20cm and height 20cm.

{ width = 20 cm and height = 20 cm }

We have to find the distance covered and displacement of the ant.

Total distance travelled by an ant per stair is (20 + 20) cm i.e. 40 cm.

Total number of stairs climbed by an ant are 5.

So, distance covered by an ant on five stairs = 40*5 cm = 200 cm

In second part we have to find the Displacement of an ant.

Displacement means shortest path between initial and final points or positions.

We have given in question, width (base) 20 cm and height (perpendicular) 20 cm.

Using Pythagorean theorem,

H² = P² + B²

→ H² = (20)² + (20)²

→ H² = 400 + 400

→ H = √800

→ H = 20√2 cm

For five stairs = 5*20√2 = 100√2 cm

Therefore, the distance covered is 200 cm and displacement is 100√2 cm.

Answer 2

GIVEN :-

An Ant climbs up five stairs each of the width 20 cm and height 20 cm.

• Width of each stair = 20 cm

• Height of each stair = 20 cm

TO FIND :-

Total distance covered and displacement of the ant.

SOLUTION :-

The ant covers a distance of 20 + 20 = 40 cm for each stair. (20 cm for moving on the stair, and 20 cm for climbing the stair).

Number of stairs = 5

Total distance covered = 5 × 40

⇒Total distance covered = 200 cm

$\rule{200}{2}$

For displacement, it is the shortest path covered.

(Refer the attachment)

Using Pythagoras theorem, we can find the displacement for each stair :-

H² = P² + B²

⇒ H² = (20)² + (20)²

⇒ H² = 400 + 400

⇒ H = √800

⇒ H = 20√2 cm

Total number of stairs = 5

Total displacement = 5 × 20√2

⇒Total displacement = 100√2 cm

Hence, the ant covers a distance of 200 cm and has an overall displacement of 100√2 cm.