an ant climbs up five stairs , each of width 20cm & height 20cm . Find the distance and displacement cover by the ant
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Distance= 200cm.
It climbs 20 widths and
20 height which means 5 stairs
So (20+20) for each step and 5 such stairs
so (20+20)*5=200cm.
Displacement=100√2 cm.
In this instead of width and height,
its hypotenuse is taken into calculation.
Hypo. of 20 width nd 20 height =20√2 ⇒ for 1 stair, nd for such 5 stairs (20√2)*5 =100√2cm.
It climbs 20 widths and
20 height which means 5 stairs
So (20+20) for each step and 5 such stairs
so (20+20)*5=200cm.
Displacement=100√2 cm.
In this instead of width and height,
its hypotenuse is taken into calculation.
Hypo. of 20 width nd 20 height =20√2 ⇒ for 1 stair, nd for such 5 stairs (20√2)*5 =100√2cm.
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1
Given: An ant is scramping on the stairs
There are '5' stairs and each stair has a width of 20 cm and a height of 20 cm.
To Find: distance travelled by the art to scramp the stairs
Displacement
Solution:
Distance travelled in one step = 20 + 20 = 40 cm
Disatnce travelled in 5 steps = 5 * 40= 200 cm = 2 m
distance travelled by the art to scramp the stairs = 200 cm = 2m
Horizontal Distance = 20 * 5 = 100 cm = 1 m
Vertical Distance = 20 * 4 = 100 cm = 1 m
Displacement = √1² + 1² =
= √ 2 m
= 100√ 2 cm
distance travelled by the art to scramp the stairs = 200 cm = 2m
Displacement = √ 2 m = 100√ 2 cm
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