Question

An ant is at corner of a cubical room of side a. The ant can move with a constant speed u. The minimum time taken to reach the farthest corner of the cube is?

Answer 1

"Suppose ant has to go from D to B

Shortest route is the line joining BD

Length of BD $= \sqrt {{(2a)^2}+{a^2}}$

$= a \sqrt {s}$

Speed =u  

Time taken $= \frac {2 \sqrt s}{u}$

The time taken by the ant is $= \frac {2 \sqrt s}{u}$

A cuboid has six faces, it comprises six rectangle. It is generally a three dimensional shape. Time refers to the period taken by an object to complete an action."