Question

an ant is moving around a few food pieces of different shapes scattered on the floor. For which food pieces would the ant have to take a longer round?

the figure of the food pieces is shown in the above attachment
please answer this question correctly​

Answer 1

Step-by-step explanation:

For measuring a round ,

We need to calculate the circumference

$(a) \tt\: c=\frac{2\pi r}{2} \\ \tt =\frac{22}{7}\times\frac{1.4}{10}\times10 \\ \tt =4.4cm$

Perimeter =2.8cm+4.4cm

=7.2cm

$(b) \tt \: \: Perimeter=2.8cm+1.5cm+1.5cm+\pi\times\left(1.4\right) \\ \tt=10.2cm$

$(c) \tt \: Perimeter=2cm+2cm+\pi\left(1.4\right) \\ \tt =8.4cm$

Answer 2

Step-by-step explanation:

$\sf(a) Radius \: of \: the \: semicircle \: part \: = ( \frac{2.8}{2} ) cm = 1.4 cm \\ \sf \: The \: perimeter \: of \: the \: food \: piece \: = 2.8 cm + πr \\ \sf= 2.8 cm + ( \frac{22}{7} × 1.4) cm \\ \sf= 2.8 cm + 4.4 cm \\ \sf= 7.2 cm$

$\sf (b) Radius \: of \: semicircle \: part = \frac{2.8}{2} = 1.4 cm \\ \sf \: Perimeter of the food piece = 1.5 cm + 2.8 cm + 1.5 cm + πr \\ \sf \: = 5.8 cm + ( \frac{22}{7} × 1.4) cm \\ \sf= 5.8 cm + 4.4 cm \\ \sf= 10.2 cm$

$\sf(c) \: Radius \: of \: the \: food \: piece \: = \frac{2.8}{2} = 1.4 cm \\ \sf Perimeter \: of \: the \: food \: piece \: = 2 cm + πr + 2 cm \\ \sf= 4 cm + ( \frac{22}{7} × 1.4) cm \\ \sf= 4 cm + 4.4 cm \\ \sf= 8.4 cm$