Question

An ant is moving in a speed of 5cm/s. Calculate distance covered in 1 hr

Answer 1

Answer:

$\boxed{Distance \: travelled \: by \: ant \: in \: 1 \: hour = 18000 \: cm \: OR \: 180 \: m \: OR \: 0.18 \: km}$

Given:

Speed of ant = 5cm/s

To Find:

Distance covered by ant in 1 hr

Explanation:

$1 \: hr = 60 \: min \\ = 60 \times 60 \: sec \\ = 3600 \: sec$

Let the distance covered be 'd'

So,

$= > Speed = \frac{Distance}{Time} \\ \\ = > 5 = \frac{d}{3600} \\ \\ = > d = 3600 \times 5 \\ \\ = > d = 18000 \: cm \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: OR\\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{18000}{100} \: m \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 180 \: m \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: OR \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{180}{1000} \: km \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 0.18 \: m$