Question

An ant is moving with a constant speed of 2m/minute .What distance will it travel in 45 seconds? Calculate the distance in m,cm and km.

Answer 1

Solution:-

This question can be easily solved by unitary method.

In 60 seconds the ant covers the distance = 2 m
In 1 second it will cover the distance = 2/60
In 45 seconds it will cover the distance = (2*45)/60
= 1.5 m
Distance in m = 1.5 m
Distance in cm = 1.5*100 = 150 cm
Distance in km = 1.5/1000 = 0.0015 km

Answer.

Answer 2

Answer:

Ant travels in 1 minute = 2 m

1 minute = 60 seconds

So, Ant travels in 60 seconds  = 2 m

So, Ant travels in 1 second  =$\frac{2}{60}$  m

So, Ant travels in 45 seconds  =$\frac{2}{60} \times 45 =1.5$m

So, The Ant travels 1.5 m in 45 seconds

1 m =100 cm

1.5 m = $1.5 \times 100 = 150 cm$

Distance traveled in 45 seconds in cm is 150 cm

1000 m = 1 km

So, 1 m = $\frac{1}{1000} km$

So, 1.5 m = $\frac{1}{1000} \times 1.5  km$

So, 1.5 m = $0.0015km$

Distance traveled in 45 seconds in km is 0.0015 km