Math, asked by kumardeepak0520, 9 months ago

An ant leaves the anthill for its morning exercise. It walks 4 feet east and then makes a 160 degree turn to the right and walks 4 more feet. It then makes another 160 degree turn to the right and walks 4 more feet. If the ant continues this pattern until it reaches the anthill again, what is the distance in feet it would have walked?

Answers

Answered by singindre824
1

Answer:

36 according to resonance

Step-by-step explanation:

But other are giving answer as 72

Answered by 23saurabhkumar
0

Answer:

Total distance travelled by ant = 72 m

Step-by-step explanation:

In the question,

Distance travelled by the ant in one turn = 4 feet

Turn made by the ant in one time = 160°

Now,

For every turn it is left of the original position by,

180° - 160° = 20°

So,

Therefore, for the ant to be where it was originally it has to complete its 360° revolution.

Therefore,

Number of turns made by the ant to reach the same position is,

\frac{360}{20}=18

Therefore,

Number of turns = 18

So,

Total distance travelled by the ant = 18 x 4 = 72 m

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