Question

An ant leaves the anthill for its morning exercise. It walks 4 feet east and then makes a 160◦ turn to the right and walks 4 more feet. It then makes another 160◦ turn to the right and walks 4 more feet. If the ant continues this pattern until it reaches the anthill again, what is the distance in feet it would have walked?

Answer 1

Answer:

Step-by-step explanation:

=> According to the question,  It walks 4 feet east and then makes a 160◦ turn to the right and walks 4 more feet. It then makes another 160◦ turn to the right and walks 4 more feet.

Thus,  Ant walks 4 feet east and then makes a 160◦ turn to the right. That means ant turn 20° left from the opposite direction.

Hence, to reach the anthill again, ant will walk 4 feet 18 times,

360/20 = 18

=> Thus, The distance ant would have to walked:

S = 18 * 4 = 72 feet

Answer 2

Answer:

Step-by-step explanation:

Since , an ant leaves the anthill for its morning exercise

According to the question,  It walks 4 feet east and then makes a 160◦ turn to the right and walks 4 more feet. It then makes another 160◦ turn to the right and walks 4 more feet.

We generally have to find the distance, the ant will travel to reach the anthill.

Thus,  Ant walks 4 feet east and then makes a 160◦ turn to the right. That means ant turn 20° left from the opposite direction.

Hence, to reach the anthill again, ant will take  turn 20° left from the opposite direction 18 times,

360/20 = 18

Since the ant will be travelling each time 4 feet.

Thus, The distance ant would have to walked will be:

$distance = 18 \times 4 =72$

So, the ant will be travelling 72 feet to reach the anthill.