Question

An ant started walking inside a, wall clock along the circumference at 12 midnight in clockwise direction. The
ant started circling the clock at 4 times the speed of the minute hand. Sometime after 2:30 AM the ant hopped
on to the Minute hand w en it was able to reach iit.
Wha,t would have been angle between Hour hand and Minute hand when the ant hopped on to the Minute
hand? (least angle)

Answer 1

Answer:

120(degrees)

Step-by-step explanation:

Here ant is moving at 4 times spped than minutes hand at 2:30 the ant is at 12(0 minutes) and minutes hand is at 6(30 minutes) and hours hand is at 2 (15 mins) and the angle is 30(hours hand from 2-3)+90

threfore,120 degrees

Answer 2

Given: An ant started walking inside a, wall clock along the circumference at 12 midnight in clockwise direction. The ant started circling the clock at 4 times the speed of the minute hand. Sometime after 2:30 AM the ant hopped on to the Minute hand w en it was able to reach iit.

To find: Wha,t would have been angle between Hour hand and Minute hand when the ant hopped on to the Minute hand.

Solution:

A clock is usually a circle and hence, is 360°. The degree between every digit from 1 to 12 on the clock is 30°. When the time is 2:30, the hour hand is on 2 and the minute hand is on 6. Thus, the angle between 2 and 6 can be calculated as follows.

$(6-2) * 30 = 120$

So now, it is calculated that the angle between 2 and 6 is 120°.

Therefore, the angle between Hour hand and Minute hand when the ant hopped on to the Minute hand would have been 120°.