An ant starts from A and reaches F. In doing so it travels along path that is S shaped. If each side of the transversed path is same then Find the ratio of distance covered by the ant to the displacement.
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Correct option is
A
0.5cms
−1
Let us move the mirror to the point Q. Ant is covering a distance of PQ(=60cm) in 2×60s. ∠PQM=30
0
.
From similar triangle we get, ∠MQ
1
P
1
=30
0
Since ∠PQP
1
=60
0
, we get PQ=P
1
Q
1
=PP
1
=60cm
Now, PP
1
=60cm and QQ
1
=0cm.
So, the rate at which the distance between ant and its image change is
2×60
60
cm/s=0.5cm/s
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