Question

An ant travel a distance of 8cm from P to Q and then moves a distance of 6cm at right angle to PQ.find the resultant displacement.

Answer 1

Resultant displacement =
$\sqrt[2]{(8) ^{2} + {6}^{2} }$
10cm

Answer 2

PQ = 8cm

Let R be the final point.

QR = 6cm

Now the displacement = PR

ie, PR is the hypotenuse of right angled triangle PQR.

PR = √(PQ^2 + QR^2)

PR = √(8^2 + 6^2)

PR = √(64+36)

PR = √100 = 10cm

So displacement is 10cm