an ant travels a distance of 8 cm from p to q and then moves a distance of 6 cm at right angles to pq .what will be the resultant displacement
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Answered by
392
The ant travels a distance of 8 cm in a straight line from p to q and then moves 6 cm perpendicularly to the line pq.
Then the resultant displacement of the ant from p is the hypotenuse of the right angled triangle that is created by this movement.
Therefore, as per the mathematical formula, hypotenuse2 = 82 + 62 = 100.
Hence, the displacement of the ant = √100 = 10 cm, which is the longest side of a triangle.
Then the resultant displacement of the ant from p is the hypotenuse of the right angled triangle that is created by this movement.
Therefore, as per the mathematical formula, hypotenuse2 = 82 + 62 = 100.
Hence, the displacement of the ant = √100 = 10 cm, which is the longest side of a triangle.
Answered by
423
Assume a Right angle triangle with base 8 cm and height 6 cm
Then the resultant displacement will be equal to
√ ( 8 square + 6 square )
√ ( 64 + 36 )
√100
= 10 cm
THE RESULTANT DISPLACEMENT WILL BE 10 cm
HOPE IT HELPS :):):):):):)
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