Question

an ant travels a distance of 8 cm from P to Q then moves distance of 6 cm right angles to PQ. find it's resultant displacement ​

Answer 1

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• $\bf\:PQ=8\:cm$

• $\bf\:QR=6\:cm$

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☛ Resultant displacement ( PR ) = ?

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$\bf\:PR=\sqrt{{PQ}^{2}+{QR}^{2}}$

$\bf\:PR=\sqrt{{8}^{2}+{6}^{2}}$

$\bf\:PR=\sqrt{64+36}$

$\bf\:PR=\sqrt{100}$

$\bf\red{{PR=10\:cm}}$

Hence,resultant displacement (PR) will be 10 cm.

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☛ Distance :- Distance is defined as the actual length path covered by moving object.Distance doesn't have unique path.It is a scaler quantity.It is always positive.

☛Displacement :- It is the shortest distance between initial and Final point of moving object with particular direction.It is a vector quantity.It may be positive negative and zero.