Question

An ant travels a distance of 8 meter in east and 6 meter in north find the final displace ment of ant and total distance

Answer 1

Since the ant traveled a perpendicular distance , so the shortest distance will be displacement

Now by applying pythagoras theorm we get,

displacement square= 8*8 + 6*6

= 64+36

= 100

therefore displacement = 10 m

And distance = 8+6 = 14 m