An Ant travels on a right angled triangle PQR from p to r which is 13 m long.then it walks to point q travelling 12m find the displacement and distance travelled by the ant ?
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Answered by
4
Answer:
distance traveled=12+13=25m displacement =5m
Explanation:
distance traveled is the actual path taken hence we need to add both the lengths giving us distance=25m
since it is a right angle triangle right angled at Q
hence by applying pythagoras theorem
pr^2=qr^2+pq^2
qr is the displacement as it is the shortest distance between the final and initial point
qr^2=(13)^2-(12)^2
qr^2=25
qr=5m
Answered by
0
Answer:
DISTANCE TRAVELLED 12+13=25 M
DISPLACEMENT = 5M
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