An ant went 3 m 17 cm up a tree, then it came 2 m 38 cm down. How far away was it from the starting point
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Answer:
height of the pole (x) = 15 m
Climbed distance per minute (y) = 4 m
Slips (y) = 2 m in next minute
So, In 2 min he climbs 2 m.
we take, 2 min = 1 unit of time
t = 2 minutes
You can calculate required time by this formula : (we are calculating it for 14 m)
Reqd. Time = [( ht. of pole - slipped distance) / (climbed distance - slipped distance )] *T
= [(x-z) / (y-z)] *t
= [(14-2) / (4-2)] &2
= (12/2) *2
= 6 *2
= 12 minutes
And the last 1 m monkey will climb in 45 second because one he get up did not get slipped down
So, total time = 12 minutes 45 seconds.
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