An AP 5, 12, 19, ...... has 40 terms. Its last term is
308
348
268
278
Answers
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1
Step-by-step explanation:
a = 5
d = 7
last term = a40
an = a + (n - 1)d
a40 = a + (40 -1)d
= 5 + (40 - 1)(7)
= 5 + (39 × 7)
= 5 + 273
= 278
therefore the last term of AP = 278
hope you get your answer
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