Question

. An AP 5, 12, 19, … has 50 terms. Its last term is​

Answer 1

Step-by-step explanation:

Given: A.P = 5, 12, 19, … .

n = 50.

To find: last term, l => a50 = ?.

In A.P:

a = 5.

d = a2-a

=> 12-5

=> 7.

Formula of nth term:

$an = a + (n - 1) \times d$

=> A50 = 5+(50-1)×7

=> 5+49×7

=> 5+343

=> 348.