Question

an ap 5 8 11 has 40 terms find the last term also find the sum of the first 10 terms

solve it.​

Answer 1

Answer:

First Term of the AP (a) = 5 Common difference (d) = 8 - 5 = 3 Last term = a40 = a + (40 - 1) d = 5 + 39 × 3 = 122 Also a31 = a + 30d = 5 + 30 × 3 = 95 Sum of last 10 terms = n 2 n2(a31 + a40) = 10 2 102(95 + 122) = 5 × 21

an-ap-5-8-11-has-40-terms-find-the-last-term-also-find-the-sum-of-the-last-10-terms