An AP. Consist 60 terms.if the first and the last terms be 7 and retrospectively find 32nd terms
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Given,n = 60, a1 = 7,
and a60 = 125
⇒ a1 + 59d = 125
7 + 59d = 125
59d = 118
d = 118/59 = 2
a32 = a1 + 31d = 7 + 31(2) = 7 + 62
∴ a32 = 69.
and a60 = 125
⇒ a1 + 59d = 125
7 + 59d = 125
59d = 118
d = 118/59 = 2
a32 = a1 + 31d = 7 + 31(2) = 7 + 62
∴ a32 = 69.
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