An AP consist of 21 terms The sum of three term in the middle is 63 and sum of last three terms is 90 Find AP
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3a+30d=63
3a+57d=90
subtracting above equations:
d=1
a=11
so
AP is 11,12,13,14.....
3a+57d=90
subtracting above equations:
d=1
a=11
so
AP is 11,12,13,14.....
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