Question

an AP consist of 3 term whose sum is 15 and of the squares of the extreems is 59 Find the term of A P​

Answer 1

3a=15

a= 5

given (a-d)^2+(a+d)^2=58

25+d^2-2ad+25+d^2+2ad=58

50+2d^2=58

2d^2-8=0

d^2-4=0

d=2

s50=25[10+98]

=2700