Question

An AP consist of 31 terms if its 16th term is m. the sum of an AP is?​

Answer 1

Answer:

SUM OF THE AP IS 31m.

Step-by-step explanation:

$16th \: term = a + 15d = m\\ \\ s = \frac{31}{2} (2a + 30d) \\ \\ = \frac{31}{2} (2)(a + 15d) \\ \\ = 31(m) \\ \\ = 31m.$