Question

an ap consist of 50 terms of which 3rd terms is 12 last term is 106 find the ap​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Given

$t_{3} =12\\a+2d=12------1\\t_{50} =106\\a+49d=106-----2\\2-1\\47d=94\\d=2\\a+2(2)=12\\a=12-4\\a=8$

the ap is 8,10,12,14,..........