An AP consisting of 49 terms has last term 28. If the common difference (2
of the term is 0.5. Find the first term and sum of terms.
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Answer:
49th term=a+(n-1)d
28=a+(49-1)0.5
28=a+24
a=28-24
a=4
Sum of 49 terms=n/2{2a+(n-1)d}
S49=49/2(8+24)
S49=49/2×32
S49=784
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