Question

An AP consists of 25 terms of which the 4th term is
4 and 22nd term is 5. The 19th term will be​

Answer 1

Answer:

4th term =a+3d=4.....equation 1

22nd term=a+21d=5.....equation 2

subtract equation 1 from equation 2

a+21d-a-3d=5-4

18d=1

d=1/18

from equation 1

a+3d=4

a+3×1/18=4

a+1/6=4

a=4-1/6

a=24-1/6

a=23/6

19th term =a+18d=23/6 +18×1/18=23/6

19th term =3.8