Question

An AP consists of 37 terms. The sum of the three middle most terms is 225 and the sum of the last three is 429. Find the AP.

Answer 1

Given
n=37 terms 
odd no/s middle most term is 37+1/2⇒19th term
then adjacent terms and middle term are 18,19,20 th terms.
last 3 terms=35,36,37 th terms
so from this we get
     a18+a19+a20=225
a+17d+a+18d+a+19d=225
              3a+54d=225
                a+18d=75                      .....1
also a35+a36+a37=429
a+34d+a+35d+a+36d=429
              3a+105d=429
                a+35d=143                   .......2

solving 1 and 2
         a=3     d=4

Then the AP would be 3,7,11,15,19

:) Hope this helps!!!!!!!1

Answer 2

plz refer to this attachment