An AP consists of 37 terms . The sum of the three middle most terms is 225 and the sum of the last three terms is 429. Find Ap.
Answers
Answered by
0
first divide 225 by 3 so u got first 3 terms and solve it as the formula t2-t1 so u got another digit
Answered by
1
n=37
U18+U19+U20=225
a+17d+a+18d+a+19d=225
3a+54d=225....eq1
U35+U36+U37=429
a+34d+a+35d+a+36d=429
3a+105d=429....eq2
eq2-eq1
105d-54d=429-225
51d=204
d=4
d=4 in eq1
3a+54x4=225
3a=225 /54x4
a=75/216
U1=75/216
U2=4+75/216
Similar questions