Question

an ap consists of 50 gram of which 3rd term is 12 and the last term is 100 find the 29th term

Answer 1

a3=a+(3-1)d
=a+2d=12
a50=a+(50-1)d
=a+49d=100
By elimination method
Subtracting 1 from 2
We get
d=88/47
By putting d in 1
we get
a=388/47
a29=a+(29-1)d
=a+28d
=388/47+28(88/47)
=388/47+2464/47
=2852/47