An AP consists of 50 team of which 3term is 12 and the last term is 106 .find the 29therm
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T3= 12
a+2d=12 ... (i)
last term is 50
so, T50= 106
a+49d= 106 .... (ii)
compairing both equation
we get , a= 8 and d=2
then T29 = ?
a+28d
8+28×2
8+56
64
hence, the 29th term of an AP is 64
a+2d=12 ... (i)
last term is 50
so, T50= 106
a+49d= 106 .... (ii)
compairing both equation
we get , a= 8 and d=2
then T29 = ?
a+28d
8+28×2
8+56
64
hence, the 29th term of an AP is 64
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