Question

An AP consists of 50 term of which 3rd term is 12 and the last term is 106 find the 25 terms​

Answer 1

Answer:

Correct option is

A

64

a+2d=12

a+49d=106

⇒47d=94

⇒d=2

a+4=12

⇒a=8

29th term : -

a+28d=8+56=64

Answer 2

$\bf\colorbox{red}{Answer:-}$

a + 2d = 12

a + 49d = 106

47d = 94

d = 2

a + 4 = 12

a = 8

25 Th term:-

a + 24 D = 8 + 50 = 58