Question

An AP consists of 50 terms of which 3rd term is 12 and last term is 106 . Find the 29th term . ​

Answer 1

Step-by-step explanation:

n=50

t3=12

t50=106

TN= a+(n-1)d

a+2d=12 (1)

a+49d=106 (2)

by solving equations (1)and(2)

d=94/47

by substituting d value in (1) we get value of a

now,to find 29th term substitute the values of a and d in the equation

t29=a+28d

hope,it helps you.

Answer 2

Thank you for this question...!!