An AP consists of 50 terms of which 3rd term is 12 and last term is 106 find the 29th yerm
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ans is 64 a is 8 d is 2 a 29 is 64
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Answer:
n=50
a3= a+2d = 12......(i)
a50 = a+49d= 106......(ii)
(i) - (ii)
a + 2d = 12
a + 49d = 106
- - =-
-47d = - 94
d = -94/-47
d = 2
put value of D=2 in eq i
a+2d = 12
a + 2*2 = 12
a = 12-4
a = 8
a29 =
a + 28d
8+28*2
8 + 56= 64
a29= 64
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