An ap consists of 50 terms of which 3rd term is 12 and the last term is 106 find the 29th term
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here is your answer and once try to solve it yourself
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N = 50
T_3 = 12
L = 106
T_3 = a + 2d
12 = a + 2d
T_50 = a + 49d
106 = a + 49d
a = 12 - 2d
a = 106 - 49d
12 - 2d = 106 - 49d
49d - 2d = 106 - 12
47d = 94
d = 2
a = 12 - 4
a = 8
T_29 = a + (n- 1) d
T_29 = 8 + 28(2)
T_29 = 64
I hope that helps you
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