Question

an ap consists of 50 terms of which 3rd term is 12 and the last term is 106 find the 29th term​

Answer 1

Answer:

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Answer 2

We know that

an=a+(n-1)d

Given 3rd term is 12

a3= a+(3-1)d

12= a+2d

a=12-2d .........(1)

Given last term is 106

Last term =50th term=106

a50= a+(50-1)d

106= a+49d

a=106-49d .........(2)

From (1) and (2), we get

12-2d=106-49d

-2d+49d=106-12

47d=94

d=2

putting the value of d in (1 )

a=12-2(2)

a=12-4

a=8

Now we need to find 29th term

We know that

an=a+(n-1)d

Putting values

a29=8+(29-1)2

=8+56

=64

Hence, 29th term is 64