An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th
term.
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Answer: a3= a+2d = 12 and
an= 106= a+49d
now, an-a3=106-12
=94
a+49d-a-2d=94
47d= 94
=> d=2
then , a= 8
now, a29=a+28d
= 8+28(2)
=8+56= 64
therefore, 29 th term is 64
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