An AP consists of 50 terms of which 3rd term is 12 and the last term is 106 find the sum of 25 terms.
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Answer:
An AP consists of 50 terms of which 3rd term is 12 and the last term is 106 find the sum of 25 terms.
a+2d=12
a+49d=106
⇒47d=94
⇒d=2
a+4=12
⇒a=8
29 term:-
a+ 28d = 8+56= 64
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Answered by
2
Explanation:
a3 = a + (3 — 1) d
12 = a + 2d
12 – 2d = a... (1)
a50 106
050 = a + (50 – 1) d
106 = a + 49d
106 – 49d = a.... (2)
12 - 2d = 106 – 49d
-2d + 49d = 106 – 12
d=2
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