An ap consists of 50 terms of which 3rd term is 12 and the last term is 106 find the 29 term
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a3=a+2d =12-----1
a50=a+49d=106-------2
Equating both equations
a=8
d=2
a29=8+(29-1)2
a29=64
Therefore 64 is the 29th term of the ap
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NikhilRajput0009:
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