Question

An AP consists of 50 terms of which the third term is twelve and the last term is 106 . Find the 29th term of the AP

Answer 1

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Answer 2

3rd term = a+2d = 12
50th term=a+49d= 106
by solving this we get, -47d= -94, d= 2,a= 8
29th term = a+28d= 8+28*2= 8+56=64