Question

An AP consists of 50 terms of which third term is 12 and the last term is 188 find the 39th term

Answer 1

Answer:

146.7

Step-by-step explanation:

In an A.P. n th term = a + (n-1)d

Given,

3 rd term = 12 ⇒ a + 2d = 12 ---->(1)

50 th term = 188 ⇒ a + 49d = 188---->(2)

(2) - (1) ⇒ 47d = 176

d = 176/47

a = 12 - (352/47) = 212/47

Now 39 th term = a + 38d

= 212 / 47 + 38(176/47)

= 4.510638297872340425531914893617 + 142.29787234042553191489361702128

≈146.7

HOPE IT HELPS YOU!!

Answer 2

for this problem we use a formula

an=a+(n-1)d

Step-by-step explanation:

before that we meed to find a

so, a+49d=188

a+2d = 12

50d=200

d=200/50

d=4

so,a+2.4=12

a+8. =12

a=12/8

a=3/2

a=1.5

so,an=a+(n-1)d

188=1.5+(39-1)4

188=1.5+(38)4

188=1.5+152

188=153.5

39th term=34.5