An AP consists of 50 terms of which third term is 12 and the last term is 106. Find the 29th term.
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Answered by
5
Step-by-step explanation:
Given,
a+(3-1)d=12 ( 3rd term )
a+2d=12........(1)
a+(50-1)d=106 ( last term---50th term)
a+49d=106.....(2)
Subtracting eq(1) from eq(2)
a+49d=106
-(a+2d=12)
47d=94
d=2............(4)
a+2d=12
a+2(2)=12
a+4=12
a=8..............(5)
29th term= a+(n-1)d
=8+(29-1)2
=8+28(2)
=8+56
=64
Answered by
33
Answer:
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