Question

An ap consists of 50term of which 3rd term is 12 and last term is 106find the 29th term

Answer 1

Answer:

64

Step-by-step explanation:

Let first term is a and cd=d

Then a3=a+2d=12-----------(1)

and a50=a+49d=106------------(2)

subtract (1) from (2) we get

47d=106-12=94

d=94/47=2

form(1)

a+2*2=12

a+4=12

a=12-4=8

Hence 29th term

a29=a+28d=8+2*28

=8+56

=64

Answer 2

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