An AP consists of 60 terms if the first and last term be 7and 125 respectively find 32 term
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a=7
d=?
An=125
n=60
An=a+(n-1)d
125=7+(60-1)d
118=59d
d=2
Now......
a=7
d=2
n=32
An=7+(32-1)2
7+31×2
7+62
=69
I hopes that it will help u
d=?
An=125
n=60
An=a+(n-1)d
125=7+(60-1)d
118=59d
d=2
Now......
a=7
d=2
n=32
An=7+(32-1)2
7+31×2
7+62
=69
I hopes that it will help u
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