Question

an AP consists of 60 terms. if the first and the last term are 7 and 125 respectively. find the 31st term​

Answer 1

Answer:

Given,n = 60, a1 = 7,

and a60 = 125

⇒ a1 + 59d = 125

7 + 59d = 125

59d = 118

d = 118/59 = 2

a31 = a1 + 30d = 7 + 30(2) = 7 + 60

∴ a31 = 67

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