An AP consists of 60 terms of which the 5th term is 50 and last term is 655. find the 31st term
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Step-by-step explanation:
Tn=a+(n-1)d
n=5
T5 = a+(5-1)d
50= a + 4d
a=50-4d ( equation 1)
T60 = a + 59 d
655 -59d = a ( equation 2)
from 1&2
655-59d=50-4d
605=55d
d = 605/55
d =11
therefore a = 6
T31 = a + 30d
= 6 + 330
= 336
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